Conditional Reasoning and Logical Equivalence — Khan Academy

Conditional Reasoning and Logical Equivalence — Khan Academy

Source: Khan Academy / LSAT prep series Raw file: raw/Conditional reasoning and logical equivalence - Khan Academy.md

Summary

Identifies the four variations of a conditional statement and shows which are logically equivalent and which are not. Only the contrapositive is always logically equivalent to the original. The converse and inverse are not — confusing them with valid inferences is one of the most common logical errors.

The Four Variations

Given: A → B (e.g., "Whenever I do yoga, I feel calm")

NameFormLogically equivalent?
OriginalA → B
Contrapositive¬B → ¬AYes
ConverseB → ANo
Inverse¬A → ¬BNo

Why the contrapositive is valid: If A guarantees B, then not-B is proof that A couldn't have happened. Reverse the arrow and negate both sides.

Why the converse is invalid: "If I'm calm, then I'm doing yoga." Calm has many other causes. Knowing the result doesn't prove the trigger.

Why the inverse is invalid: "If I'm not doing yoga, I'm not calm." Not doing yoga still allows other triggers of calm (sleep, vacation, a puppy). Absence of one sufficient condition doesn't eliminate the result.

Forming a Contrapositive with Multiple Terms

When the original has compound conditions (AND or OR), the contrapositive requires an extra step.

Example: "If I'm skateboarding, I will wear a helmet and protective gloves."

Diagram: Skateboarding → helmet and gloves

Step 1 — Flip: Move everything on the left to the right and vice versa.

Helmet and gloves → skateboarding (not yet equivalent)

Step 2 — Negate every term:

¬helmet and ¬gloves → ¬skateboarding (not yet equivalent)

This reads "if I'm wearing neither," which is too narrow — if I have gloves but no helmet, I'm still not skateboarding.

Step 3 — Flip AND ↔ OR:

¬helmet or ¬gloves → ¬skateboarding (now equivalent)

If either piece of necessary equipment is missing, I cannot be skateboarding.

The rule: In any contrapositive, every AND becomes OR and every OR becomes AND.

Concepts